Random probability change

Want !random 1 50% 2 30% 3 20%
I am totally unclear in this regard. I want to ask someone for help.
English is not good, I am sorry.


I am not completely sure what you are looking for. Could you give some more clear examples of what kind of outputs you want from this !random command?

I have three numbers
Each number is a different chance
1 is 50%
2 is 30%
3 is 20%
Instead of 33.33%

This command setup will create a command called !random that will output “1” 50% of the time, “2” 30% of the time, and “3” 20% of the time. Just copy and paste this into chat.

!addcom -cd=5 !random $(eval a=Math.ceil(Math.random()*10);a<=5?1:(a<=8?2:3))

thank you very much!
In addition, I want to ask if there are 10 numbers at a time.
1~3 appears 10
1 1 1 1 2 3 1 2 1 3

This will give 10 numbers at a time:

!addcom -cd=5 !random $(eval b=[];for(i=0;i<10;i++){a=Math.ceil(Math.random()*10);b.push(a<=5?1:(a<=8?2:3));}b.join(` `))

Thank you again!
I will continue to ask questions next time.

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