How to use one count in two commands

Asked Jun 19, 2020·5 replies·Last activity 6 years ago·Open in Discord ↗

Nutty MammothOriginal postJun 19, 2020

ex.
!commands add !number1 $(eval var count = '$(count)'; text : ${count} text ${count} text)
!commands add !number2 $(eval var count = '$(count)'; text : ${count} text ${count} text)

1. !number1 -> text 1 text 1
2. !number1 -> text 2 text 2
3. !number2 -> text 1 text 1 (x)
text 3 text 3 (o)
4. !number1 -> text 4 text 4

I have two commands that output the same content.
However, when number1 is entered, the command of number2 is not output, but can the count be increased?
The opposite is also true.
In other words, I want to modify so that one count is shared by the two commands number1 and number2.
Is this possible......

5 replies

Polar CatJun 19, 2020

Hey @Nutty Mammoth!

It looks like an alias command would be the fit for your case:

!addcom !number1 $(eval var count = `$(count)`; `text : ${count} text ${count} text`)
!addcom !number2 -a=!number1

Nutty MammothJun 20, 2020

Sorry. This command does not work. -> !addcom !number2 -a=!number1
And I corrected the number 3 in the text.

1. !number1 -> text 1 text 1
2. !number1 -> text 2 text 2
3. !number2 -> text 1 text 1 (x)
text 3 text 3 (o)
4. !number1 -> text 4 text 4

Polar CatJun 20, 2020

You must have made a mistake when you entered the commands, because it does work:

Polar CatJun 20, 2020

If you're setting up the command from the dashboard, the following might help you...

The -ul= , -a= , and -cd= parameters are to be used only if you add the commands from the chat, if you use the dashboard to add new commands you have to fill the boxes corresponding to each parameters:

Nutty MammothJun 20, 2020

Thanks for the reply. I solved this problem perfectly thanks to your help. Thank you very much. T^T

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