Filter not working as intended: filter()

2022 visit: it’s fun seeing where I started, now JavaScript is my best friend.

I doubt this post will be useful to you though, as some bit of code was in a Pastebin that is now deleted.


Hello there!

I’m not sure my filter work as intended, the command selects 9 names at random and the latest name from the list, and supposedly filters out the names that have already been randomly selected to avoid duplicates, yet I still have duplicates from time to time. Where did I mess up?

$(eval var u="$(urlfetch json https://pastebin.com/raw/knfwxExT)".split(",");u.pop();var t=(u.length)+1;var l=u.pop();var s=[];for(i=0;i<9;i++){u.filter(x=>!s);s[i]=u[Math.floor(Math.random()*u.length)];}s=s.join(", ");"Here\'s a small selection of streamer\'s kids: "+s+", and "+l+". Total: "+t+" kids. Consult the full list here: https://pastebin.com/raw/knfwxExT";)

Thanks in advance!

@Emily

Instead of using filter(), you can use the array splice() method to remove elements from an array at a given index:

$(eval a=`$(urlfetch json https://pastebin.com/raw/knfwxExT)`.split(`,`);a.pop();d=a.length;b=[];c=a.pop();for(i=0;i<9;i++){b.push(a.splice(Math.floor(Math.random()*a.length),1));}`Here's a small selection of streamer's kids: ${b.join(`, `)}, and ${c}. Total: ${d} kids. Consult the full list here: https://pastebin.com/raw/knfwxExT`)
1 Like

Oh wow, that’s a very smart way to deal with it, I learned something new today, thank you very much! :heart:

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